Goal: create a function
minMax(arr)that returns an object with the minimum and maximum value from the array.
Math.min and Math.max/**
* minMax(arr): returns an object with the minimum and maximum value of the array.
* Examples:
* minMax([1, 2, 3]) -> { min: 1, max: 3 }
* minMax([-5, 0, 10]) -> { min: -5, max: 10 }
* @param {number[]} arr — input array of numbers
* @returns {{ min: number, max: number }}
*/
function minMax(arr) {
let min = arr[0]; // Initialize minimum with first element
let max = arr[0]; // Initialize maximum with first element
// Iterate through the array starting from the second element
for (let i = 1; i < arr.length; i++) {
if (arr[i] < min) min = arr[i]; // Update minimum if necessary
if (arr[i] > max) max = arr[i]; // Update maximum if necessary
}
return { min, max }; // Return result as an object
}Why this approach:
function minMax(arr) {
return {
min: Math.min(...arr),
max: Math.max(...arr)
};
}Why this approach:
function minMax(arr) {
return arr.reduce((acc, val) => {
if (val < acc.min) acc.min = val;
if (val > acc.max) acc.max = val;
return acc;
}, { min: arr[0], max: arr[0] });
}Why this approach:
reduceWrite a function minMax that returns an object with the minimum and maximum value from the array.
minMax([1, 2, 3]); // { min: 1, max: 3 }
minMax([-5, 0, 10]); // { min: -5, max: 10 }minMaxmin and maxGoal: create a function
minMax(arr)that returns an object with the minimum and maximum value from the array.
Math.min and Math.max/**
* minMax(arr): returns an object with the minimum and maximum value of the array.
* Examples:
* minMax([1, 2, 3]) -> { min: 1, max: 3 }
* minMax([-5, 0, 10]) -> { min: -5, max: 10 }
* @param {number[]} arr — input array of numbers
* @returns {{ min: number, max: number }}
*/
function minMax(arr) {
let min = arr[0]; // Initialize minimum with first element
let max = arr[0]; // Initialize maximum with first element
// Iterate through the array starting from the second element
for (let i = 1; i < arr.length; i++) {
if (arr[i] < min) min = arr[i]; // Update minimum if necessary
if (arr[i] > max) max = arr[i]; // Update maximum if necessary
}
return { min, max }; // Return result as an object
}Why this approach:
function minMax(arr) {
return {
min: Math.min(...arr),
max: Math.max(...arr)
};
}Why this approach:
function minMax(arr) {
return arr.reduce((acc, val) => {
if (val < acc.min) acc.min = val;
if (val > acc.max) acc.max = val;
return acc;
}, { min: arr[0], max: arr[0] });
}Why this approach:
reduceWrite a function minMax that returns an object with the minimum and maximum value from the array.
minMax([1, 2, 3]); // { min: 1, max: 3 }
minMax([-5, 0, 10]); // { min: -5, max: 10 }minMaxmin and maxThe code editor is intentionally hidden on mobile.
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